SOLUTION: s is the sum of the first 100 consecutive positive even integers , and t is the sum of the first 100 consecutive positive integers . s is what percent greater than t ? a 10

Question 310338: s is the sum of the first 100 consecutive positive even integers , and t is the sum of the first 100 consecutive positive integers . s is what percent greater
than t ?
a 100% b 50% c 10% d 2% e 1%
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
s is the sum of the first 100 consecutive positive even integers , and t is the sum of the first 100 consecutive positive integers . s is what percent greater
than t ?
a 100% b 50% c 10% d 2% e 1%
1/2 * n(n+1) = sum all numbers from 1 to n
n^2 = sum 1st n odd numbers
n(n+1) = sum 1st n even numbers
s/t = 100(101)/(1/2 * 100 * 101) = 10100/(50 * 101) = 10100/5050 = 2
answer is a) 100%

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