SOLUTION: 5 times the first of three consecutive even integers is 4 less than twice the sum if the second and third, find the integers a^5 -4 this is as far as I got

Question 309883: 5 times the first of three consecutive even integers is 4 less than twice the sum if the second and third, find the integers
a^5 -4 this is as far as I got
Answer by mananth(16949) (Show Source): You can put this solution on YOUR website!
let the first integer be x
the second will be x+2
The third will be x+4
.
5 times the first integer = 5x.
sum of second and third = x+2 + x+4
= 2x+6
Twice the sum of second and third
2(2x+6)
4 less than 2(2x+6)
= 2(2x+6)-4
.
5x=2(2x+6)-4
5x=4x+12-4
x= 8
.
The numbers are 8 , 10, 12
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