SOLUTION: find three consecutive even integers such that the product of the second and third integers is twenty more than ten times the first integer

SOLUTION: find three consecutive even integers such that the product of the second and third integers is twenty more than ten times the first integer

Algebra.Com

Question 309869: find three consecutive even integers such that the product of the second and third integers is twenty more than ten times the first integer
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Let the 3 even integers be: x, x+2 & x+4
(x+2)(x+4)=10x+20
x^2+6x+8-10x-20=0
x^2-4x-12=0
(x-6)(x+2)=0
x-6=0
x=6 ans.
Proof:
(6+2)(6+4)=10*6+20
8*10=60+20
80=80
x+2=0
x=-2 ans.
Proof:
(-2+2)(-2+4)=10*-2+20
0*2=-20+20
0=0

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