SOLUTION: Three consecutive integers are such that the square of the first is 29 less then the product of the other two

SOLUTION: Three consecutive integers are such that the square of the first is 29 less then the product of the other two

Algebra.Com

Question 307893: Three consecutive integers are such that the square of the first is 29 less then the product of the other two
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Here is your equation and you can finish:
x^2 = (x + 1)(x + 2) - 29
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