SOLUTION: The least integer of a set of consecutive integers is -25. If the sum of these integers is 26, how many integers are in this set?
(A) 25 (B) 26 (C) 50 (D) 51 (E) 52
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Question 303188: The least integer of a set of consecutive integers is -25. If the sum of these integers is 26, how many integers are in this set?
(A) 25 (B) 26 (C) 50 (D) 51 (E) 52
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
The least integer of a set of consecutive integers is -25. If the sum of these integers is 26, how many integers are in this set?
(A) 25 (B) 26 (C) 50 (D) 51 (E) 52
1/2 * n(n+1) = 1/2 * 25 * 26 = 325
the sum of the 25 negative integers is the same as the sum of the 25 positive integers multiplied by -1 so that adds up to 0, the 51st integer is 0 itself, the 52nd integer is 26
(E) 52
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