SOLUTION: find 3 consecutive integer that the product of the first is 23 more than the 3rd integer

Question 295504: find 3 consecutive integer that the product of the first is 23 more than the 3rd integer
Answer by alicealc(293) (Show Source): You can put this solution on YOUR website!
1st integer = x
2nd integer = x + 1
3rd integer = x + 2

x - 5 = 0 or x + 5 = 0
x = 5 or x = -5

so,there are 2 answers:
1st integer = x = 5
2nd integer = x + 1 = 5 + 1 = 6
3rd integer = x + 2 = 5 + 2 = 7
or
1st integer = x = -5
2nd integer = x + 1 = -5 + 1 = -4
3rd integer = x + 2 = -5 + 2 = -3

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