SOLUTION: Find four consecutive even integers such that the sum of the squares of the first and the second is 12 more than the last.

SOLUTION: Find four consecutive even integers such that the sum of the squares of the first and the second is 12 more than the last.

Algebra.Com

Question 288967: Find four consecutive even integers such that the sum of the squares of the first and the second is 12 more than the last.
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Here are the 4 consecutive even integers:
x
x + 2
x + 4
x + 6
Here is the equation you need to solve this problem:
x^2 + (x + 2)^2 = (x + 6) + 12

RELATED QUESTIONS
Find four consecutive even integers such that the sum of the squares of the first and the (answered by rapaljer,solver91311)

find four consecutive even integers such that the sum of the squares of the first and the (answered by solver91311)

Find 3 consecutive even integers such that the sum of the first and four times the second (answered by stanbon)

Find three consecutive even integers such that the sum of twice the first and three times (answered by math_tutor2020,josgarithmetic)

Find three consecutive even integers such that twice the sum of the first and third is... (answered by mananth)

Find three consecutive even integers such that twice the sum of the first and third is... (answered by mananth)

Find four consecutive even integers such that two times the sum of the first and second... (answered by KMST)

Find three consecutive even integers such that the sum of the squares of the first and... (answered by josmiceli)

find four consecutive even integers such that 2 times the sum of the first and second is... (answered by checkley77)