SOLUTION: 1. find three consecutive even integers such that one fourth the sum of the first and the third is equal to 22 less than the second. Thank you tutor!..:)

Question 287784: 1. find three consecutive even integers such that one fourth the sum of the first and the third is equal to 22 less than the second.
Thank you tutor!..:)
Found 2 solutions by dabanfield, richwmiller:
Answer by dabanfield(803) (Show Source): You can put this solution on YOUR website!
find three consecutive even integers such that one fourth the sum of the first and the third is equal to 22 less than the second.
Thankyou tutor!..:)
Let x, x+2 and x+4 be the three consecutive even integers.
Then we have:
1/4*(x + (x+4)) = (x+2) - 22
Solve the above equation for x and then calculate x+2 and x+4.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
(1/4)(n+n+4)=n+2-22
1/4*(2n+4)=n-20
n/2+1=n-20
n/2=n-21
n=2n-42
42=n
42,44,46
check
1/4*(42+46)=44-22
22=22
ok
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