SOLUTION: find three consecutive positive integers such that the product of the second and third integers is twenty more than ten times the first integer

Algebra.Com
Question 281696: find three consecutive positive integers such that the product of the second and third integers is twenty more than ten times the first integer
Answer by Greenfinch(383)   (Show Source): You can put this solution on YOUR website!
If the numbers are X, X+1 and X+2
10X = (X+1)(X+2) - 20
10X = X^2 + 7X -18
X^2 -7X -18 =0
(X+2)(X-9) = 0
X = -2 or 9
since 2 is negative, the numbers are 9,10,11
CHECK 90 is 20 less than 110

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