SOLUTION: Three consecutive even integers are such that the square of the first plus the square of the third is 136. Find the three integers

SOLUTION: Three consecutive even integers are such that the square of the first plus the square of the third is 136. Find the three integers

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Question 276188: Three consecutive even integers are such that the square of the first plus the square of the third is 136. Find the three integers
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
n^2+(n+4)^2=136
n^2+n^2+8n+16=136
2*(n^2+4n+8)=136
n^2+4n+8=68
n^2+4n-60=0
(n+10)*(n-6)=0
n=6 n=-10
(6,8,10) and (-10,-8,-6)
6^2+10^2=136

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