SOLUTION: if you take a certain two-digit number and reverse its digits to get another two-digit number, then add these two numbers together, their sum is 132. what is the original number?

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Question 275504: if you take a certain two-digit number and reverse its digits to get another two-digit number, then add these two numbers together, their sum is 132. what is the original number?
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
if you take a certain two-digit number and reverse its digits to get another two-digit number, then add these two numbers together, their sum is 132. what is the original number?
Let the digit in the units place be y
& in the tens place be x
So the number will be 10x+y
On reversing the digits
the number becomes 10y+x
The sum of the two = 132
10x+y + 10y+x= 132
11x+11y=132
x+y=12
To satisfy this equation only three pairs are possible
48, 57, 66
All the three numbers wheen reversed and added give you 132

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