SOLUTION: the sum of the squares of two consecutive odd positive intergers is 202. find the integers

Question 273784: the sum of the squares of two consecutive odd positive intergers is 202. find the integers
Found 2 solutions by solver91311, Alan3354:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Let represent the smaller of the two odd integers. Then is the next consecutive odd integer.

The square of the smaller is

The square of the larger is

The sum of the two squares is:

and this sum is equal to 202, so:

Solve this easily factorable quadratic and discard the negative root since the problem asks for a positive integer. The positive root is the smaller of the two odd integers and the other odd integer is 2 larger.

John

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
202/2 = 101
which is in the center
--> 9 & 11

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