SOLUTION: Find three consecutive integers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third.

Question 264530: Find three consecutive integers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third.
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
Find three consecutive integers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third.
3 consecutive integers --> x, x+1, x+2
2*x + 4*(x+1) = 2*(x+2) + 20
2x + 4x + 4 = 2x + 4 + 20
6x + 4 = 2x + 24 (rearrange)
6x - 2x = 24 - 4
4x = 20
x = 5
therefore x+1 = 6 and x+2 = 7 AND the three consecutive integers are
5, 6, 7

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