SOLUTION: ind three consecutive odd integers such that the product of the first and second exceeds the third by 8.

Question 262216: ind three consecutive odd integers such that the product of the first and second exceeds the third by 8.
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
three consecutive odd integers such that the product of the first and second exceeds the third by 8
.
Let x = first consecutive odd integer
then
x+2 = second consecutive odd integer
x+4 = third consecutive odd integer
.
x(x+2) = (x+4) + 8
x^2 + 2x = x + 12
x^2 +x -12 = 0
(x-3)(x+4) = 0
x = {3,-4}
.
Since -4 is an even number toss out the solution.
.
The three odd integers:
3,5,7

RELATED QUESTIONS
ind three consecutive odd integers such that the product of the first and second exceeds... (answered by drk)

Find three consecutive odd integers such that the product of the first and the second... (answered by ewatrrr)

ind three consecutive odd integers such that twice the first and third plus three times... (answered by Alan3354)

Find three consecutive odd interrgers such that the product of the first and the second... (answered by stanbon)

find three consecutive odd integers such that twice the sum of the first and third... (answered by scott8148,ewatrrr)

Find three consecutive odd intergers such that the product of the first and the seconds... (answered by MathLover1)

Find 3 consecutive odd integers such that 3 times the product of the first and third... (answered by CubeyThePenguin)

Find three consecutive odd integers such that the product of the first and the second... (answered by jim_thompson5910)

Find three consecutive negative integers such that 3 times the product of the first and... (answered by stanbon)