SOLUTION: the product of two consecutive integers is 71 more than their sum.Find the integers.

Question 260639: the product of two consecutive integers is 71 more than their sum.Find the integers.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
the product of two consecutive integers is 71 more than their sum.Find the integers.
Let the number be x.
the consequtive number will x+1
the product of the two numbers = x*(x+1)
x*(x+1) = x + x+1 +71 ------------- 1 (71 more than the sum of the two numbers)
x^2+x = 2x+72
x^2+x-2x-72=0
x^2-x-72=0
x^2-9x+8x-72=0
x(x-9) + 8(x-9) = 0
(x-9)(x+8)=0
so x= 9 or -8
The value of -8 satisfies the condition in equation 1
So the numbers are -8 and -7

M Ananth------------ mananth@hotmail.com

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