You can put this solution on YOUR website! the product of two consecutive integers is 8 less than 8 times their sum. find the integers.
let one number be x
then the other number will be x+1
x(x+1) is the product
x+(x+1) = sum of the numbers
8(x+x+1) = eight times their sum
8(x+x+1)- 8 (less 8)
x(x+1) = 8(x+x+1)-8
x^2+x = 8x+8x+8-8
x^2 + x -16x= -8
x^2-15x=0
x(x-15)=0
x=0 or 15
x cannot be zero. so the numbers are 15, 16
