x = 1st odd integer x+2 = 2nd odd integer x+4 = 3rd odd integer x+6 = 4th odd integerSubtract 12 from all three sides Divide through by 4 The only odd integer x between 8.5 and 10.5 is 9. So there is just one set: x = 1st odd integer = 9 x+2 = 2nd odd integer = 11 x+4 = 3rd odd integer = 13 x+6 = 4th odd integer = 15 sum = 9+11+13+15=48 Edwin