SOLUTION: divide and simplify so that there are no radicals in the denominator. show your steps.
1. square root 7 over 100
2. square root of 18 + square root 24 over square root of 6
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Question 252926: divide and simplify so that there are no radicals in the denominator. show your steps.
1. square root 7 over 100
2. square root of 18 + square root 24 over square root of 6
3. 8 over square root of 6
Found 3 solutions by richwmiller, dabanfield, drk:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
1. no radical in the denominator
2.sqrt(18)+sqrt(24) /(sqrt(6))
factor
sqrt(6)*sqrt(3)+sqrt(6)*sqrt(4)/sqrt(6)
sqrt(6)*(sqrt(3)+sqrt(4))/sqrt(6)
I leave the rest for you
3.8/sqrt(6)
multiply by sqrt(6)/sqrt(6)
3.8*(sqrt(6)/6
I leave it for you to simplify.
Answer by dabanfield(803) (Show Source): You can put this solution on YOUR website!
divide and simplify ao that there are no radicals in the denominator. show your steps.
1. square root 7 over 100
2. square root of 18 + square root 24 over square root of 6
3. 8 over square root of 6
(1.) sqrt(7/100) = sqrt(7)/sqrt(100) = sqrt(7)/10
(2.) (sqrt(18) + sqrt(24)) / sqrt(6)
Multiply numerator and denominator by sqrt(6):
sqrt(6)*((sqrt(18)+sqrt(24)) / [sqrt(6)*sqrt(6)] =
[sqrt(6*18) + sqrt(6*24)] / 6 =
[sqrt(108) + sqrt(144)] / 6 =
[sqrt(36*3) + 12] / 6 =
[6*sqrt(3) + 12] / 6 =
sqrt(3) + 2
(3.) 8/sqrt(6)
Again multiply numerator and denominator by sqrt(6):
8*sqrt(6) / [sqrt(6)*sqrt(6)] =
8*sqrt(6) / 6 =
(4/3)*sqrt(6)
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
divide and simplify so that there are no radicals in the denominator. show your steps.
1. square root 7 over 100
I will assume the question looks like this:
we get
which is
/
--
2. square root of 18 + square root 24 over square root of 6
( + ) /
simplify sqrt(18) as 3sqrt(2) and sqrt(24) as 4sqrt(6)
() /
multiply by conjugate, sqrt(6), on both numerator and denominator to get
()* /
distribute to get
() /
simplify the numerator to get
/
and then factor out a 6 to get
.
--
3. 8 over square root of 6
multiply by conjugate, sqrt(6) on both top and bottom to get
reduce to get
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