SOLUTION: find three consecutive even integers so that the largest is 2 times more than the smallest

Question 252725: find three consecutive even integers so that the largest is 2 times more than the smallest
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
We need three consecutive even integers. We don't know what they are. Some examples are:
2,4,6 ; 4,6,8 ; 6,8,10 and so on.
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Notice that the second number is 2 more than the first.
Notice the third number is 4 more than the first.
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Since we don't know the first number, call is X.
The second number is 2 more than this, it is X + 2.
Third number is 4 more than this, it is X + 4.
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So, Three consecutive even integers can be expressed as: X, X+2, X+4.
Two times the smallest is the largest means
(i) 2X = X + 4,
since the smallest was X and the largest was X + 4.
subtract X from both sides to get
X = 4.
Now
the first number was X. It is X = 4,
the second number was X + 2, it is 4 + 2 = 6
the third number is X + 4, it is 4 + 4 = 8.
The three numbers are 4 , 6, 8
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