SOLUTION: find two consecutive positive integers such that the square of the second integer added to 6 times the first is equal to 181 help me please :)

Question 245504: find two consecutive positive integers such that the square of the second integer added to 6 times the first is equal to 181
help me please :)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Let

represent the first integer. Then the next consecutive integer is

.

The square of the second:

6 times the first:

So:

Put in standard form:

Solve the factorable quadratic. Exclude the negative root because the problem asks for a positive integer. The positive root is the first integer, one more than that is the second one.

John

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