SOLUTION: Find three consecutive odd integers whose sum is 10 less than 4 times the least integer.

Question 241822: Find three consecutive odd integers whose sum is 10 less than 4 times the least integer.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
three consecutive odd integers whose sum is 10 less than 4 times the least integer.
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
Solve the boundary condition.
6x+3 = 4(2x-1)-10
6x+3 = 8x-14
2x = 17
x = 17/2
--------------------------
Boundary answer:
1st; 17-1 = 16
2nd: 18
3rd: 20
------------------------
Solution for the inequality
6x+3 < 4(2x-1)-10
1st = 15
2nd = 17
3rd = 19
=====================
Cheers,
Stan H.
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