SOLUTION: four consecutive odd integers such the smallest is 25 less than the sum of the two latgest integers

Question 235913: four consecutive odd integers such the smallest is 25 less than the sum of the two latgest integers
Answer by Stitch(470) (Show Source): You can put this solution on YOUR website!
Equation 1: The 4 integers in term of the smallest one. We increase each number by two because you only want the odd numbers.
Equation 2: combine like terms
Subtract X from both sides
Add 15 to both sides

Now plug 15 in for X into equation 1 to get the 4 numbers
Equation 1:
Simplify

Check your answers
-------------------
19 + 21 = 40
40 - 25 = 15

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