SOLUTION: The sum of three consecutive integers is 47 less than the least of the integers. Show work to understand

Question 228196: The sum of three consecutive integers is 47 less than the least of the integers. Show work to understand
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
The sum of three consecutive integers is 47 less than the least of the integers. Show work to understand.

Step 1. Let n be the first and the least of the integers.

Step 2. Let n+1 and n+2 be the next two consecutive integers.

Step 3. Let n+n+1+n+2 be the sum of the three consecutive integers.

Step 4. Let n-47 be 47 less than the least of the integers

Step 5. Then n+n+1+n+2=n-47 since the sum of three consecutive integers is 47 less than the least of the integers

Step 6. Solving n+n+1+n+2=n-47 leads to the following steps

Subtract 3 from both sides of the equation

Subtract n from both sides of the equation

Divide by 2 to both sides of the equation

and

Check if sum if 47 less than the least.

which is a true statement

Step 7. ANSWER: The three consecutive numbers are -25, -24, and -23.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J

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