SOLUTION: three consecutive odd integers such that seven times the sum of the first two integers is three more than nine times the third integer.

SOLUTION: three consecutive odd integers such that seven times the sum of the first two integers is three more than nine times the third integer.

Algebra.Com

Question 224169: three consecutive odd integers such that seven times the sum of the first two integers is three more than nine times the third integer.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Let x, x+2 & x+4 be the 3 odd integers.
7(x+x+2)=9(x+4)+3
7(2x+2)=9x+36+3
14x+14=9x+39
14x-9x=39-14
5x=25
x=25/5
x=5 the smallest integer.
5+2=7 the middle integer.
5+4=9 the largest integer.
Proof:
7(5+7)=9*9+3
7*12=81+3
84=84

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