SOLUTION: four consecutive even integers whose sum is 120

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: four consecutive even integers whose sum is 120      Log On


   

Question 218408: four consecutive even integers whose sum is 120
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Four consecutive even integers whose sum is 120.

Step 1. Let n be one even integer.

Step 2. Let n+2, n+4, and n+6 be the next three consecutive integers.

Step 3. Let n+n+2+n+4+n+6=120 since the sum of four even and consecutive even integers is 120.

Step 4. Solving yields the following steps.

4n%2B12=120

Subtract 12 from both sides of the equation.

4n%2B12-12=120-12

4n=108

Divide by 4 to both sides of the equation.

4n%2F4=108%2F4

n=27 and n%2B2=29 n%2B4=31 n%2B6=33

Check their sum...27+29+31+33=120...which is a true statement.

Step 5. ANSWER: The numbers are 27, 29, 31, and 33.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J
http://www.FreedomUniversity.TV