SOLUTION: find three consecutive even integers so that the sum of the smallest interger and twice the second integer is 20 more than the third
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Question 215785This question is from textbook intermediate algebra with applications
: find three consecutive even integers so that the sum of the smallest interger and twice the second integer is 20 more than the third
This question is from textbook intermediate algebra with applications
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Let x, x+2 & x+4 be the 3 integers.
x+2(x+2)=(x+4)+20
x+2x+4=x+4+20
3x+4=x+24
3x-x=24-4
2x=20
x=20/1
x=10 ans. for the smallest integer.
10+2=12 for the middle integer.
10+4=14 ans. for the largest integer.
Proof:
10+2*12=14+20
10+24=34
34=34
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