SOLUTION: The Sum of the squares of two consecutive positive intergers is 85.Find the Integers.
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Question 212038: The Sum of the squares of two consecutive positive intergers is 85.Find the Integers.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let x = the first positive integer, the x+1 = the next consecutive positive integer. The sum of the squares of these is 85.
Simplify.
Subtract 1 from both sides.
Divide both sides by 2.
Subtract 42 from both sides.
Factor the trinomial.
or so...
or Ignore the negative solution.
The two integers are: 6 and 7
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