SOLUTION: Find three consecutive odd integers such that 4 times the sum of the last two is 2 greater than 10 times the first.
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Question 20883: Find three consecutive odd integers such that 4 times the sum of the last two is 2 greater than 10 times the first.
Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
4(x+2x+4)=2+10(x)
8x+12=2+10x
8x=-10+10x
-2x=-10
x=5
Hence the three consective numbers are 5,7 and 9.
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