SOLUTION: ``an elderly wildbeest scents a lion and starts running away at 40mph. .02hours later (about 1 minute ) the lion starts running after the wildbeest at 50mph. presuming the lion and
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Question 205682This question is from textbook algebra 1 an integrated approach
: ``an elderly wildbeest scents a lion and starts running away at 40mph. .02hours later (about 1 minute ) the lion starts running after the wildbeest at 50mph. presuming the lion and the wildbeest started from the same spot, how long will it take the lion to catch the wildbeest? use the 5 step process, also be sure to draw a distance and fill in a table to set up the problem.
here is the five step method
use variables to represent your unknowns
draw a diagram
draw a table
set up and solve your equations
check
This question is from textbook algebra 1 an integrated approach
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
``an elderly wildbeest scents a lion and starts running away at 40mph. .02hours later (about 1 minute ) the lion starts running after the wildbeest at 50mph. presuming the lion and the wildbeest started from the same spot, how long will it take the lion to catch the wildbeest?
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In 0.02 hrs at 40 mph the wildebeest goes 0.8 miles, so he's that far from the lion.
The lion gains on him at 10 mph (50-40).
0.8/10 = 0.08 hours = 4.8 minutes.
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This is fiction. A lion wouldn't wait 0.02 hours, then start chasing something.
Lions don't run 50 mph, and can't run over about 20 mph for 4.8 minutes.
How elderly is this wildebeest than can run 40 mph for 5 minutes?
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