SOLUTION: find four consecutive odd integers whose sum is 416

Question 204164: find four consecutive odd integers whose sum is 416
Found 2 solutions by RAY100, Alan3354:
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Let the four consecutive ODD integers be, x,x+2,x+4,x+6
.
sum = 416,,,x+(x+2)+(x+4)+(x+6) = 416
.
4x +12 =416
.
4x = 404
.
x=101,,,,,,,numbers are,,,101,,103,,,105,,107,,,
.
check,,,,sum to 416,,,ok
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The average will be the "center" of the 4 integers.
416/4 = 104.
There are 2 odd integers just below 104 and 2 above.
= 101, 103, 105, 107
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Save time, do it the easy way.
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