SOLUTION: the product of two consecutive integers is 8 less than 10 times the smaller of the two integers. Find the integers.
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Question 197732: the product of two consecutive integers is 8 less than 10 times the smaller of the two integers. Find the integers.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
X(X+1)=10X-8
X^2+X-10X+8=0
X^2-9X+8=0
(X-8)(X-1)=0
X-8=0
X=8 ANS.
X-1=0
X=1 ANS.
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