SOLUTION: Find 2 consecutive odd intergers such that three times the first minus the second equals 24
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Question 192345: Find 2 consecutive odd intergers such that three times the first minus the second equals 24
Found 2 solutions by Alan3354, Earlsdon:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find 2 consecutive odd intergers such that three times the first minus the second equals 24
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n = 1st integer
n+2 = 2nd integer
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3n -(n+2) = 24
2n-2 = 24
2n = 26
n = 13
integers = 13 and 15
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let x = the first odd integer and x+2 = the next consecutive odd integer.
From the problem description, you can writ:
3x-(x+2) = 24 Simplify and solve for x.
3x-x-2 = 24 Add 2 to both sides and combine the x-terms on the left.
2x = 26 Divide both sides by 2.
x = 13 and x+2 = 15.
The two consecutive odd integers are:
13 and 15
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