SOLUTION: If the first and third consecutive integers are added, the result is 63 less than five times the second integer. Find the third integer.

Question 186401: If the first and third consecutive integers are added, the result is 63 less than five times the second integer. Find the third integer.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Let the three integers = x, x+1, x+2
:
If the first and third consecutive integers are added, the result is 63 less than five times the second integer.
x + (x+2) = 5(x+1) - 63
2x + 2 = 5x + 5 - 63
2x - 5x = 5 - 63 - 2
-3x = -60
x =
x = +20 is the 1st integer
:
Find the third integer.
20 + 2 = 22 is the 3rd integer
:
:
Check solution:
first and third consecutive integers are added, the result is 63 less than
five times the second integer.
20 + 22 = 5(21) - 63
42 = 105 - 63
42 = 42
RELATED QUESTIONS
If the first and third of three consecutive odd integers are added together, the result... (answered by Earlsdon)

if the first and third of three consecutive odd integers are added, the result is 63 less (answered by mangopeeler07)

if the first and third of three consecutive odd integers are added, the result is 63 less (answered by solver91311)

If the first and third of three consecutive odd integers are added, the result is 57 less (answered by Mathtut)

If the first and third of three consecutive odd integers are added, the result is 45 less (answered by stanbon)

If the first and third of three consecutive odd integers are added, the result is 87 less (answered by Alan3354)

If the first and third of three consecutive odd integers are added, the result is 57 less (answered by checkley77)

If the first and third of three consecutive odd integers are added, the result is 87 less (answered by MathLover1)

If the first and third of three consecutive odd integers are added, the result is 81 less (answered by Alan3354)