SOLUTION: The sum of the squares of two consecutive intergers is 25.

Algebra.Com
Question 185158: The sum of the squares of two consecutive intergers is 25.
Answer by vleith(2983)   (Show Source): You can put this solution on YOUR website!
let x be one number, then (x+1) is the other number





x = -4 and x = 3
so then numbers are 3,4 and -4,-3

RELATED QUESTIONS

The sum of the squares of two consecutive positive intergers is 85. What are the... (answered by Paul)
the sum of the squares of two consecutive positive even intergers is 340. find the... (answered by JimboP1977)
My question: The sum of the squares of two consecutive positive intergers is 85; Find... (answered by wgunther)
The Sum of the squares of two consecutive positive intergers is 85.Find the... (answered by Earlsdon)
the sum of the squares of two consecutive odd positive intergers is 202. find the... (answered by solver91311,Alan3354)
find two consecutive positve intergers such that the sum of there squares is... (answered by jim_thompson5910)
Find two consecutive positive intergers the sum of whose squares is... (answered by tommyt3rd)
The differnece between the squares of two consecutive positive odd intergers is 24. Find... (answered by checkley71)
The sum of the squares of two consecutive positive intergers is 164 find the... (answered by wuwei96815,olayinka003)