SOLUTION: four times the smallest of three consecutive odd integers is 236 more than the sum of the two integers. find the integers.

Question 184506: four times the smallest of three consecutive odd integers is 236 more than the sum of the two integers. find the integers.
Found 2 solutions by kailuen, solver91311:
Answer by kailuen(7) (Show Source): You can put this solution on YOUR website!
x
x+2
X+4
4(x)=(x+2)+(x+4)+236
4x=2x+6+236
2x=242
X= 121
X+2=123
X+4= 125
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

The only way your question makes any sense at all is if you left out the word other when you typed your question. I suspect your question is supposed to be:

"Four times the smallest of three consecutive odd integers is 236 more than the sum of the other two integers. Find the integers."

In the future, please take more care when you post. We tutors do enough work just answering the questions you guys pose without having to guess at what you mean.

Having vented my spleen, let's answer the question that I think you meant to ask.

Let the smallest odd integer be x.

Then the next consecutive odd integer must be x + 2.

And the next consecutive odd integer after that must be x + 2 + 2 = x + 4.

Four times the smallest is

"is" means equals

The sum of the other two is:

236 more than that is:

Putting it all together:

Solve for x to get the smallest integer. Add 2 to get then next one, and add 2 more to get the largest one.

John

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