SOLUTION: Three times the smallest of three consecutive even integers is two more than twice the largest. Find the integers.
This what I tried.
3x=2[x+2+2(x+4)]
3x=2[x+2+2x+8]
3x=2[
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Question 184353: Three times the smallest of three consecutive even integers is two more than twice the largest. Find the integers.
This what I tried.
3x=2[x+2+2(x+4)]
3x=2[x+2+2x+8]
3x=2[3x+10]
3x=6x+20
-6x=-6x
3x-6x=20
-3x=20
x=20/-3
x=?
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
"Three times the smallest of three consecutive even integers is two more than twice the largest" ----> 3(2x)=2(2x+4)+2
3(2x)=2(2x+4)+2
6x=2(2x+4)+2
6x=4x+8+2
6x-4x=8+2
2x=10
x=5
Nums: 2*5, 2*5+2, 2*5+4 ---> 10, 12, 14
Ans: numbers are 10, 12, 14
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