SOLUTION: The sum of an integer and three times the next consecutive integer is 47. What is the original integer.

Question 183825: The sum of an integer and three times the next consecutive integer is 47. What is the original integer.
Found 2 solutions by checkley77, halbren:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x+3(x+1)=47
x+3x+3=47
4x=47-3
4x=44
x=44/4
x=11 ans.
11+1=12 ans
Proof:
11+3*12=47
11+36=47
47=47

Answer by halbren(10) (Show Source): You can put this solution on YOUR website!
x is the first integer and x+1 is the next
By the question
x+3(x+1)=47
Distribute
x+3x+3=47
Combine the variables
4x+3=47
Subtract 3 from both sides
4x=44
Divide both sides by 4
x=44/4=11
If x=11 then x+1=12
Check
x+3(x+1)=11+3(12)=11+36=47

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