SOLUTION: What are two consecutive odd integers whose product is 23 more than their sum.

Algebra.Com
Question 183495: What are two consecutive odd integers whose product is 23 more than their sum.
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
x(x+2)=x+(x+2)+23
x^2+2x=2x+2+23
x^2+2x-2x-25=0
x^2-25=0
(x-5)(x+5)=0
x-5=0
x=5 ans.
x+2=7 ans.
Proof:
5*7=5+7=23
35=12+23
35=35



RELATED QUESTIONS

find two consecutive odd integers whose product is 23 more than their... (answered by Mathtut)
Find two consecutive odd integers whose product is 23 more than their... (answered by checkley77,Alan3354)
Find two consecutive odd integers whose product is 23 more than their... (answered by Alan3354)
The product of two consecutive odd integers is 23 more than their sum. Find the... (answered by Fombitz)
Find two consecutive odd intergers whose product is 23 more than their... (answered by user_dude2008)
Find two consecutive odd integers whose product is 79 more than their... (answered by jim_thompson5910)
Find two consecutive odd integers whose product is 79 more than their... (answered by jim_thompson5910)
find two consecutive odd integers whose product is 39 more than three times their... (answered by josmiceli)
What are three consecutive integers whose product is 693 more than their... (answered by josgarithmetic,Alan3354)