SOLUTION: find three consecutive integers such that the product of the two smaller inters is 2 more than ten times the largest integers.

Question 177196: find three consecutive integers such that the product of the two smaller inters is 2 more than ten times the largest integers.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let the three consecutive integers be: x, (x+1) and (x+2)
"The product of the two smaller integers (x and (x+1)) is 2 more than 10 times the larger integer (x+3).
Subtract 10x from both sides.
Subtract 32 from both sides.
Factor this quadratic equation.
Apply the zero product rule.
or so...
or
Solutions:
11, 12, and 13
-2, -1, and 0
As you can see, there are two solutions, so let;'s check them both!
x = 11

OK!
x = -2

OK!

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