SOLUTION: Find three consecutive even integers such that the sum of the larger two integers is 54 more than the smallest integer.

Question 175727: Find three consecutive even integers such that the sum of the larger two integers is 54 more than the smallest integer.
Answer by EMStelley(208) (Show Source): You can put this solution on YOUR website!
Call the first integer x. Then the next two can be represented by x+2 and x+4 (think about 2,4,6 as an example). Then the "sum of the larger two" would be (x+2) + (x+4) and "54 more than the smallest integer" would be x+54. So we have the equation

Subtracting x from both sides and subtracting 6 from both sides, we get

Thus, the three consecutive even integers are 48, 50, and 52.
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