SOLUTION: The sum of even integers between 1 and 48

Question 169946: The sum of even integers between 1 and 48
Answer by chiefman(11) (Show Source): You can put this solution on YOUR website!
taking the formula n+1,n+3,n+5....where n=1,2,3,4,........to get even integers we have
2,4,6,8,.......48 this becomes an arithmetic series ie
2+4+6+8+......+48 where first term(a)=2,common diffrence(d)=2
we first find the number of terms in this seies
using the formula where L is the last term.
48=2+(n-1)2
n=24 therefore there are 24 terms.
Now we find the the sum using the formula
where S=sum n=number of terms
S=[24/2(2*2+(24-1)2]
=12(4+46)
=600
therefore the sum is 600
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