SOLUTION: the product of two consecutive even integers is 106 less than 11 times their sum.find the two integers

Question 165828: the product of two consecutive even integers is 106 less than 11 times their sum.find the two integers
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
X(X+2)=11(X+X+2)-106
X^2+2X=11(2X+2)-106
X^2+2X=22X+22-106
X^2+2X-22X-22+106=0
X^2-20X+84=0
(X-14)(X-6)=0
X-14=0
X=14 ANSWER.
X-6=0
X=6 ANSWER.
PROOFS:
14*16=11(14+16)-106
224=11*30-106
224=330-106
224=224
---------------
6*8=11(6+8)-106
48=11*14-106
48=154-106
48=48

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