SOLUTION: the product of two consecutive even integers is 168

Question 164095: the product of two consecutive even integers is 168
Found 3 solutions by elima, EthanT.Terrell, MathTherapy:
Answer by elima(1433)   (Show Source): You can put this solution on YOUR website!
1st integer = x
2nd integer = x+2
======================
x(x+2)=168

(x+14)(x-12)=0
x+14=0
x=-14
x-12=0
x=12
=================
So we end up with 2 possibilities;
x = 12 or x = -14
Now we need our second;
x + 2 = 12+2=14
x+2 = -14+2=-12
====================
When x = 12, the second integer = 14
When x = -14, second integer = -12
:)

Answer by EthanT.Terrell(1)   (Show Source): You can put this solution on YOUR website!
x(x+2)=168
x^2+2x=168
-168 -168
x^2+1x-168=0
(x+14)(x-12)
x+14=0 or x-12=0_
x=-14 X=12
-14 reflects to 14
_________
Solutions= 14, 12

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
the product of two consecutive even integers is 168

Let the 1st integer be F

Then the 2nd consecutive even integer is F + 2

Since the product of the integers is 168, then we'll have: F(F + 2) = 168

(F + 14)(F - 12) = 0

F = - 14 or 12

If the 1st even integer is - 14, then the second consecutive even integer is - 12. Or, if the 1st even integer is 12, then the second consecutive even integer is 14.

Therefore, the 2 integers are either or
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