SOLUTION: Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91.

Question 162521: Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91.
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91.
.
Let x = first (smallest) consecutive integer
x+1 = second consecutive integer
x+2 = third consecutive integer
x+3 = fourth (largest) consecutive integer
.
2[(x+2)+(x+3)] = 3x+91
2[2x+5] = 3x+91
4x+10 = 3x+91
x+10 = 91
x = 81
.
Therefore, the integers are:
81, 82, 83, and 84

RELATED QUESTIONS
Find four consecutive integers such that twice the sum of the two greater integers... (answered by sdmmadam@yahoo.com)

Find four consecutive integers such that twice the sum of the two greater integers... (answered by venugopalramana)

Find four consecutive integers such that twice the sum of the two greater integers... (answered by josmiceli)

Find four consecutive intergers such that twice the sum of the two greater intergers... (answered by checkley75)

1) The lesser of tow consecutive even integers is 10 more than one-half the greater. Find (answered by stanbon)

Find four consecutive integers such that three times the sum of the last two exceeds... (answered by mananth)

Not from a text book, from worksheet. Find four consecutive intergers such that twice... (answered by ankor@dixie-net.com)

Find four consecutive integers such that the sum of the first three exceeds twice the... (answered by vleith)

find four consecutive odd integers such that twice the sum of the third and fourth... (answered by pakhi)