SOLUTION: Hello, I need help please! The question is Find two consecutive odd integers such that six more than nine times the first integer is five times the second integer. Find the integ
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Question 156696: Hello, I need help please! The question is Find two consecutive odd integers such that six more than nine times the first integer is five times the second integer. Find the integers. Thank you
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Consecutive odd integers are integers that are odd and are next to one another. So numbers like 1,3,5,7,etc are consecutive odd integers. Algebraically, they follow the form , , , etc. where "x" is any integer.
Also, because "six more than nine times the first integer is five times the second integer", this translates to where is the first number and is the second number
Start with the given equation.
Distribute.
Combine like terms on the left side.
Subtract from both sides.
Subtract from both sides.
Combine like terms on the left side.
Combine like terms on the right side.
Divide both sides by to isolate .
Reduce.
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Now move onto the expression for the first number
Plug in .
Multiply and to get .
Combine like terms.
So the first number is 1.
Now move onto the expression for the second number
Plug in .
Multiply and to get .
Combine like terms.
So the second number is 3.
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Answer:
So the two numbers are 1 and 3
Check:
works.
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