SOLUTION: 3 times the first of three consecutive numbers is 4 more than 2 times the second

Question 143607: 3 times the first of three consecutive numbers is 4 more than 2 times the second
Answer by nabla(475) (Show Source): You can put this solution on YOUR website!
Let's write symbols for the three numbers:
n1=x
n2=(x+1)
n3=(x+2)
So, we want 3n1=3x to be 4 more than 2n2=2(x+1)
Which is:
3x=2(x+1)+4
3x=2x+6
x=6.
This is the first number. The second number is x+1=6+1=7.
So the numbers are 6 and 7.
check:
3*6=18
2*7=14
18-14=4!

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