SOLUTION: The sum of three consecutive positive integers is 246. Find the largest integer.

Question 1429: The sum of three consecutive positive integers is 246. Find the largest integer.
Found 4 solutions by usyim88hk, DeepaEvangeline, khwang, Lhairel Ramones:
Answer by usyim88hk(158)   (Show Source): You can put this solution on YOUR website!
let x be the biggest one
x+(x-1)+(x-2)=246
x+x-1+x-2=246
3x=249
x=83
Answer by DeepaEvangeline(15)   (Show Source): You can put this solution on YOUR website!
Let x, x+1 and x+2 be the three consecutive positive integers.
Sum of three consecutive integers is 246.
x + x+1 + x+2 = 246
3x + 3 = 246
3x = 246 - 3 = 243
x = 243/3 = 81
Therefore the three consecutive positive integers are 81, 81+1 and 81+2.
The largest integer is 83.
Answer by khwang(438)   (Show Source): You can put this solution on YOUR website!
Let x-1, x and x+1 be the three consecutive positive integers.
Solve x-1 +x + x+1 = 246
So, 3x =246, x = 82
The largest among them is 82 + 1 = 83

Answer by Lhairel Ramones(1)   (Show Source): You can put this solution on YOUR website!
Let x= first consecutive positive integers.
x+1 = second
x+2= third
x + (x+1) + (x+2)
3x + 3 (-3) = 246 (-3)

3x = 243
3/243
x = 81 the first
x+1 = 81+1= 82 the second
x+2 = 81 +2 = 83 the third
so th answer is 81,82 and 83
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