SOLUTION: Find four consecutive even integers such that the sum of the first three excedds the fourth by 8.

Question 141693: Find four consecutive even integers such that the sum of the first three excedds the fourth by 8.
Found 2 solutions by stanbon, aiman anees:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find four consecutive even integers such that the sum of the first three exceeds the fourth by 8.
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1st: 2x
2nd: 2x+2
3rd: 2x+4
4th: 2x+6
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EQUATION:
6x + 6 = 2x+6 + 8
4x = 8
x = 2
1st: 4
2nd: 6
3rd: 8
4th: 10
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Cheers,
Stan H.

Answer by aiman anees(1) (Show Source): You can put this solution on YOUR website!
1st 2x
2nd 2x+2
3rd 2x+4
4th 2x+6
EQUATION
6x+6=2x+6+8
6x-2x=6+8+6
4x=8
4x/4=8/4(divide both sides by 4)
x=2
1st=2x
=2(2)
=4
2nd=2x+2
=2(2)+2
=4+2
=6
3rd=2x+4
=2(2)+4
=4+4
=8
4th=2x+6
=2(2)+6
=4+6
=10
four consecutive integers are 4 6 8 10
by aiman anees
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