SOLUTION: Find three consecutive odd integers such that the sum of the first and twice the second is 6 more than the third

Question 135336: Find three consecutive odd integers such that the sum of the first and twice the second is 6 more than the third
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let x = the first odd number, then x+2 is the next consecutive odd number and x+4 is the next one.
From the problem description, you can write:
x+2(x+2) = (x+4)+6 Simplify and solve for x.
x+2x+4 = x+10
3x+4 = x+10 Subtract x from both sides.
2x+4 = 10 Subtract 4 from both sides.
2x = 6 Divide both sides by 2.
x = 3 and...
x+2 = 5 and...
x+4 = 7
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