SOLUTION: find three consecutive intergers that eual out to be 45.... when i did it my teacher counted it wrong...my answer was 14, 15, 16...i guess she wants me to show her how i got it?

Question 13369: find three consecutive intergers that eual out to be 45....
when i did it my teacher counted it wrong...my answer was 14, 15, 16...i guess she wants me to show her how i got it??? can you help me with this?

Answer by elima(1433) (Show Source): You can put this solution on YOUR website!
find three consecutive intergers that equal out to be 45....
Let x be the first integer; so we have
x; then the second integer would be x+1; then the third would br x+2;
x+(x+1)+(x+2)=45
We add all the x's and the ones together:
3x+3=45
We subtract 3 from both sides;
3x+3-3=45-3
3x=42
Divide 3 from both sides;

x=14
So the first integer would be 14; then the second 14+1=15; and the third 14+2=16
So we have 14+15+16=45
=)
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